if sin a = 2/5, find the value of 21 +21 tan
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sin a = 2/5 = p/h
h^2 = p^2 + b^2
25 = 4 + b^2
21 = b^2
b = √21
tan a = p/b = 2/√21
tan^2 a = 4/21
21 + 21 tan ^2a
21 ( 1+tan^2 a )
21 ( 1 + 4 /21 )
21 ( 21+4)/21
21+4
25 ✓✓✓✓✓✓✓✓✓✓✓✓
h^2 = p^2 + b^2
25 = 4 + b^2
21 = b^2
b = √21
tan a = p/b = 2/√21
tan^2 a = 4/21
21 + 21 tan ^2a
21 ( 1+tan^2 a )
21 ( 1 + 4 /21 )
21 ( 21+4)/21
21+4
25 ✓✓✓✓✓✓✓✓✓✓✓✓
sahidsmith19pestnh:
answer is 25
have you seen the photo that i attached with it
now it is correct
at the end there is tan^2 a
in the question
ya I know
thank you
I changed my answer
thank you
welc
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1
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hope it helps ....
it is ur correct answer
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