Math, asked by noobsonu615, 12 hours ago

If sin θ = a^2-b^2/a^2+b^2, then find cosec θ+ cot θ (a) a/a+b (b) b+a/b-a (c) a^2/a+b (d) a+b/a-b​

Answers

Answered by skadakash
0

Answer:

the answer is b+a/b-a...

please mark me the brainliest answer...

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