Question

If sin (A + 2B) = √3/2 and cos (A + 4B) = 0, A > B

Answer 1

Answer

sin (A + 2B) = √3/2

⇒ A + 2B = 60º

cos (A + 4B) = 0

⇒ A + 4B = 90°

Solving, we get A = 30°, B = 15°

Answer 2

Answer:

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