Question

If sin (A + 2B) = √3/2 and cos (A + 4B) = 0, A>B and A + 4B≤90°then find A and B.

Answer 1

Answer:

A=0 and  B=π/6

Step-by-step explanation:

sin(A+2B)=√3/2

then  A+2B=sin^-1 (√3/2)

       A+2B=π/3

and

cos(A+4B)=0

then  A+4B=cos^-1(0)

        A+4B=π/2

on solving   we get A=0 and B=π/6

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