Math, asked by meghabst040, 8 months ago

If sin( A + 2B) = √3/2 and cos( A + 4B) = 0, then A+B=​

Answers

Answered by angelina10
3

Answer:

45°

Step-by-step explanation:

 \sin(a + 2b)  =    \frac{ \sqrt{3} }{2} \\  \sin(60)   =  \frac{ \sqrt{3} }{2}  \\ so \: a + 2b = 60 \:  >  > equation \: 1

 \cos(a + 4b)  = 0 \\  \cos(90)  = 0 \\ a + 4b = 90 \:  >  > equation \: 2

equation 2 - equation 1

2b=30°

b=30/2=15°

substitute value of b in equation 1

a + 2(15°) = 60°

a + 30°. = 60°

a = 60°-30°

a = 30°

So A+B=30°+15°=45°

Similar questions