Math, asked by alankritbajoria100, 9 months ago

if sin(a+2b)=√3/2 and cos(a - b)=1 find a and b

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Answered by piyushnehra2006
1

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Answered by hasini4669
0

a = 20° b = 20 °

sin (a +2b) = √3 / 2

w.k.t ,

sin 60° = √3 /2

so, a+ 2b = 60° ............ 1

cos (a - b ) = 1

w.k.t,

cos 0° = 1

so, a - b= 1

a = b ................. 2

substitute 2 in 1 ,

b + 2b = 60

3b = 60

b = 20°

From 2 , a = 20°

Therefore , a =20 ° and b = 20°

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