if sin(a+2b)=√3/2 and cos(a - b)=1 find a and b
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a = 20° b = 20 °
sin (a +2b) = √3 / 2
w.k.t ,
sin 60° = √3 /2
so, a+ 2b = 60° ............ 1
cos (a - b ) = 1
w.k.t,
cos 0° = 1
so, a - b= 1
a = b ................. 2
substitute 2 in 1 ,
b + 2b = 60
3b = 60
b = 20°
From 2 , a = 20°
Therefore , a =20 ° and b = 20°
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