Question

If sin(A+2B)=√3/2,cos(2A-B)=1/√2 find the value of A and B​

Answer 1

Answer:

A = 30° and B = 15°

Step-by-step explanation:

sin(A+2B)=√3/2

sin(A+2B)=Sin 60°

A+2B=60°

A=60°-2B Let take it equation 1

cos(2A-B)=√1/2

cos(2A-B)=cos 45°

2A-B=45°

Now put value of A from equation 1

2(60°-2B)-B=45°

120°-4B-B=45°

-5B=45°-120°

-5B= -75°

5B = 75°

B=75/5

B=15°

Put value of B in equation 1

A=60°-2×15°

A=60°-30°

A=30°