Math, asked by puls, 11 months ago

if sin(A-2B)=root 3/2and cos(A+4B)=0,A>B and A+4B greater or equal to 90​

Answers

Answered by Anonymous
5

Answer: A = 70 ; B = 5

Step-by-step explanation:

Sin (A-2B) = root3/2 = Sin 60 ....(i)

Cos(A+4B) = 0 = Cos 90 ...(ii)

From (i) === A - 2B = 60  ........(iii)

From (ii) === A + 4B = 90 ........(iv)

(iv) - (iii)

4B - -2B = 90-60

6B = 30

B = 5

(iii)=> A - 2B = 60

A - 2*5 = 60

A = 70


puls: thanx
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