If sin(a+2b)=root3/2 & cos(a+4b)=0 find a & b
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Hi Mate!!!
Sin ( a + 2b ) = Sin ( 60 ) => a + 2b = 60 ... 1
and
Cos ( a + 4b ) = Cos ( 90 ) => a + 4b = 90 ...2
Subtract 1 from 2
2b = 30°
b = 15°
and
a = 30°
Have a nice time..
Sin ( a + 2b ) = Sin ( 60 ) => a + 2b = 60 ... 1
and
Cos ( a + 4b ) = Cos ( 90 ) => a + 4b = 90 ...2
Subtract 1 from 2
2b = 30°
b = 15°
and
a = 30°
Have a nice time..
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