Math, asked by yashasvimodi54, 5 months ago

If sin a = 2mn/ m^2 + n^2 find the value of sinAcotA/cosA

Answers

Answered by subhsamavartj

0

Answer:

Step-by-step explanation:

(sinA cotA)/cosA=(sinA cosA/sinA)/cosA

=cosA/cosA=1

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