Question

if sin A=√3/2
find 3 sin -2 cos A/ 3 sinA + 2 cosA​

Answer 1

sinA=√3/2

sinA=sin60°

A=60°

now substracting A by 60° we get,

3sinA-2cosA/3sinA+2cosA

= 3sin60°-2cos60°/3sin60°+2cos60°

= 3×√3/2-(2×1/2)/(3√3/2)+2×1/2

= 3√3/2-2/3√3+1

= (3√3×3√3-2×2+6√3)/6√3

= (3×3×3-4+6√3)/6√3

= (27-4+6√3)/6√3

= (23+6√3)/6√3

That's your answer. I hope it will help you.