Question

if sin A = √3/2, find cos A and cot A​

Answer 1

$sin \: \: A \: = \frac{ \sqrt{3} }{2}$

$AC ^{2} = BC ^{2} + AB ^{2}$

${2}^{2} = BC ^{2} + ( \sqrt{3) ^{2} }$

$4 = BC ^{2} + 3$

$4 - 3 = BC ^{2}$

$1 = BC ^{2}$

$COS A = \frac{AB}{AC} = \frac{1}{2}$

$COT \: A \: = \frac{1}{tan } = \frac{1}{ \sqrt{3} }$