Question

if sin A = √3/2, find the value of 2 cot square A -1

Answer 1

sin A = √3/2sin A = sin 60°A = 60°
Now, cot A = cot 60° = 1/√3
2cot² A - 1 = 2cot² 60° - 1= 2(1/√3)² - 1= 2/3 - 1 = -1/3
Hence your required answer is -1/3
Hope This Helps You!

Answer 2

Answer: ( $\frac{-1}{3}$)

Step-by-step explanation:

• Given sin A=$\frac{\sqrt{3} }{2}$
• sin 60°=$\frac{\sqrt{3} }{2}$
• Comparing both the equations we get A=60°
• Now, $2cot^{2}A-1$

              ⇒$2cot^{2}60-1$

              ⇒$2(\frac{1}{\sqrt{3} })^{2} -1$

              ⇒$\frac{2}{3}-1$

              ⇒$\frac{2-3}{3}$

              ⇒ $\frac{-1}{3}$

• Hence,the required result is $\frac{-1}{3}$.

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