Question

if sin A=√3/2 find the value of 2 cot³ A-1.​plz... tell me the ans..

Answer 1

Answer:

Given that sin A= √3/2

which means A =60°

Now, putting the value of A in

$2 \cot {}^{3} \: a {}^{} - 1$

$2 \cot{}^{3} 60 - 1$

we know cot 60°=1/√3

$2 \times( 1 \div \sqrt{3)} {}^{3} - 1$

$2 \times 1 \div 3 \sqrt{3} - 1$

$2 \div 3 \sqrt{3} - 1$

Now if you want to further solve it then take LCM otherwise it is sufficient.

hope it helps you!!!