If sin A = √3/2, find the value of 2cot^2A-1
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Answered by
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Given :-
sinA = √3/2
We know that,
sin60° = √3/2
=> sinA = sin60°
=> A = 60°
Since, A = 60°
=> cotA = cot60°
Now cot60° = 1/√3
So cot²60° = (1/√3)²
=> cot²60° = 1/3
So 2cot²60° = 2 × 1/3
=> 2cot²60° = 2/3
Now,
2cot²A - 1
= 2cot²60° - 1
=> 2/3 - 1
=> 2/3 - 3/3
=> - 1/3
Your answer :-
Hope it helps dear friend ☺️
sinA = √3/2
We know that,
sin60° = √3/2
=> sinA = sin60°
=> A = 60°
Since, A = 60°
=> cotA = cot60°
Now cot60° = 1/√3
So cot²60° = (1/√3)²
=> cot²60° = 1/3
So 2cot²60° = 2 × 1/3
=> 2cot²60° = 2/3
Now,
2cot²A - 1
= 2cot²60° - 1
=> 2/3 - 1
=> 2/3 - 3/3
=> - 1/3
Your answer :-
Hope it helps dear friend ☺️
rishabh58:
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