If sin a 3/2 ,find the value of all t-ratios of a
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sin theta =√3/2= Perpendicular / Hypotenuse
P = √3 , H = 2
To find Base , By Pythagoras theorem;
AB²+ BC²= AC²
=> (√3)²+ BC² = 2²
=> BC² = 4 - 3
=> BC = 1
b=1 , p=√3, h=2
cos theta = b/h = 1/2
tan theta = p/b =√3/1
cosec theta = h/p = 2/√3
sec theta = h/b = 2/1
cot theta = b/p = 1/√3
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