if sin A=3/4 calculate cos A and tan A
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Answered by
36
cosA =√(1-sin^2(A))
= √(1-9/16)
= √(7/16)
= (√7)/4 [Answer-I]
tanA = sinA/cosA
= (3/4)÷((√7)/4)
= 3/√7 [Answer-II]
= √(1-9/16)
= √(7/16)
= (√7)/4 [Answer-I]
tanA = sinA/cosA
= (3/4)÷((√7)/4)
= 3/√7 [Answer-II]
Answered by
34
Hope it helps u.....
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