Question

if sin a=3/4, calculate cos a and tan a

Answer 1

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Answer 2

Answer:

$CosA = \frac{\sqrt{7}}{4}$

$tanA=\frac{3}{\sqrt{7}}$

Step-by-step explanation:

Given $sinA = \frac{3}{4}$

i ) $cosA = \sqrt{1-sin^{2}A}$

=$\sqrt{1-\left(\frac{3}{4}}\right)^{2}$

/* From (1) */

=$\sqrt{1-\frac{9}{16}}$

=$\sqrt{\frac{16-9}{16}}$

=$\sqrt{\frac{7}{16}}$

=$\frac{\sqrt{7}}{4}$---(1)

ii) $tanA = \frac{SinA}{cosA}$

= $\frac{\frac{3}{4}}{\frac{\sqrt{7}}{4}}$

After cancellation, we get

= $\frac{3}{\sqrt{7}}$---(2)

Therefore,

$CosA = \frac{\sqrt{7}}{4}$

$tanA=\frac{3}{\sqrt{7}}$

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