Math, asked by sahapriya1494, 6 months ago

If sin A =3/4, calculate cos A and tan A

Answers

Answered by ashuprakash20
0

Answer:

cos 48.59 =  0.66

tan 48.59 = 1.13388

Step-by-step explanation:

sin A = 3/4

3/4 = 0.75

A = asin(0.75)

A = 48.59 in degree

cos A = cos 48.59 =  0.66

tan A = tan 48.59 = 1.13388

Answered by Disha976
9

Given that,

  •  \rm { sin \: A = \dfrac{3}{4} }

We have to find,

  •  \rm { cos \: A \: and \: tan \: A }

Solution,

Here, we know that

 \rm { sin \: A =\dfrac{ 3}{4} = \dfrac{ Perpendicular}{Hypotenuse} }

Hence,

  •  \rm { Perpendicular = 3}
  •  \rm { Hypotenuse = 4}

_____________

Applying pythagoras property-

 \rm\red { {H}^{2} = {B}^{2} + {P}^{2} }

 \rm { \leadsto {B}^{2} = {H}^{2} - {P}^{2} }

 \rm { \leadsto {B}^{2} = {4}^{2} - {3}^{2} }

 \rm { \leadsto {B}^{2} = 16 - 9 = 7}

 \rm\blue { \leadsto B = \sqrt{7} }

________________

  •  \rm { Hypotenuse = 4 }
  •  \rm { Base =  \sqrt{7}  }
  •  \rm { Perpendicular = 3 }

 \leadsto \rm\red{ cos \: A = \dfrac{ Base}{ Hypotenuse} = \dfrac{ \sqrt{7} }{4} }

 \:

 \leadsto \rm\red{ tan \: A = \dfrac{ Perpendicular}{ Base} =  \dfrac{ 3 }{\sqrt{7}} }

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