Question

If sin A = 3/4 , calculate cos A and tan A​

Answer 1

Solution of this question is in attached pic .

Answer 2

Answer:

$\rm{ \huge{ \underline{ \underline{ \green{ ❥Answer}}}}}$

Given: sin A=3/4=BC/AC

Let BC=3k and AC=4k

Then by Pythagoras’ theorem,

AB²= AC²-BC²

=(4k)²-(3k)²

=16k²-9k²=7k²

☞ AB=k√7

Hence, Cos A= AB/BC=√7k/4k=√7/4

And tan A= BC/AB =3k/√7k=3/√7