Question

If Sin A = 3/4, Calculate cos A and tan A

Answer 1

Answer:

Sin A = 3/4

Side opposite to A/Hypotenuse = 3/4

BC/AC = 3/4

Let

BC = 3x

AC = 4x

We find AB using Pythagoras Theorem.

Step-by-step explanation:

Hope it's help you

Answer 2

I hope my answer is helpful for you

Step-by-step explanation:

Given sin A = 3/4

=>BC/DC = 3/4

=>BC= 3k and AC = 4k

where k is the constant of proportionality.

By Pythagoras theorem , we have

AB²= AC² - BC²= (4k)²- (3k)²=7k²

=>AB =√7k

so cos A = AB/AC = √7k/4k = √7/4

And tan A = BC/AB = 3k/√7k = 3/√7