Question

if sin A=3/4, calculate cos A and tan A.​

Answer 1

cosA= $\frac{\sqrt{7} }{4}$

tanA = $\frac{3}{\sqrt{7} }$

Step-by-step explanation:

Step 1:

Formulas:

sinA=$\frac{opposite}{hypoteneous}$ , cosA = $\frac{adjacent}{hypoteneous}$ , tanA= $\frac{opposite}{adjacent}$,

$opposite^{2} + adjacent^{2} = hypoteneous^{2}$

given, sinA =  so opposite=3, hypoteneous= 4

Step 2:

adjacent= $\sqrt{7}$

Therefore

cosA= $\frac{\sqrt{7} }{4}$

tanA = $\frac{3}{\sqrt{7} }$