Question

if sin a 3÷4 calculate cos A and tan A

Answer 1

here is how to get cos a.
$\sin(a) = \frac{3}{4} \\ we \: have \: the \: identity \\ {sin}^{2}(a) + {cos}^{2}(a) = 1 \\ = {\frac{3}{4} }^{2} + {cos}^{2} (a) = 1 \\ = \frac{9}{16} + {cos}^{2} (a) = 1 \\ = {cos}^{2} (a) = 1 - \frac{9}{16} \\ = {cos}^{2} (a) = \frac{7}{16} \\ = cos(a) = \frac{ \sqrt{7} }{4}$
here is how to get tan a.
$\tan(a ) = \frac{ \sin(a) }{ \cos(a) } \\ = \tan(a ) = \frac{\frac{3}{4}}{ \frac{ \sqrt{7} }{4} } \\ = \tan(a ) = \frac{3}{4} \times \frac{4}{\sqrt{7}} \\ = \tan(a ) = \frac{3}{\sqrt{7} }$

Answer 2

Here is your answer

Hope it helps u....