If Sin A = 3/4, Calculate cos A and tan A.
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Answered by
1
Answer:
cosA=√7/4, tanA=3/√7
Explanation:
BC=√AC^2-AB^2
=√4^2-√3^2
=√16-√9
=√7
cosA=BC/AC
=√7/4
tanA=AB/BC
=3/√7
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Answer:
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