Question

If sin A =3/4 , calculate
cos A and tan A
respectively.​

Answer 1

sinA=3/4

cosA=√1-sinA^2

cosA=√1-9/16

cosA=√7/4

tanA=sinA/cosA

tanA=3/√7

Answer 2

Answer:

coA=$\sqrt{7}$/4 ,, tanA=3/$\sqrt{7}$

Step-by-step explanation:

sinA=3/4.....2

sqaring both side

sin^2A=9/16

1-cos^2A=9/16   , cos^2A=7/16

cosA=$\sqrt{7}$/4 .....1

now divide 1and2

tanA=3/$\sqrt{7}$