Question

if sin A 3/4 calculate cosA and tanA​

Answer 1

Answer:

this is the answer

Explanation:

sin a=perpendicular/hypoteneous=3/4

perpendicular=3

hypotenuse =4

P^2+B^2=H^2

9+B^2=16

B^2=7

B=√7

cos a =B/H=√7/4

tan a=P/B=3/√7

Answer 2

Answer:

sqrt(7)/4  and  3/sqrt (7)

Explanation:

• we know that cos² A + sin² A = 1
• so cos A = $\sqrt{1-sin^{2} A}$
• cos A = $\sqrt{1-(9/16)}$ = $\frac{\sqrt{7} }{4}$
• tan A = sin A / cos A
• tan A = (3/4)/($\frac{\sqrt{7} }{4}$)
• tan A = 3/sqrt(7)