Question

if sin A= 3/4, calculate sec A
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Answer 1

sinA =3/4

sinA=p/h

P=3k

H=4k

by Pythagoras theorem

(H)2=(P)2+(B)2

(B)2=(H)2-(p)2

(b)2 =(4k)2-(3k)2

(b)2=16k2-9k2

(b)2=7k2

b=rout7 k

secA=H/B

secA=4k/rout 7 k