If sin A=3/4 find cos A
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here, sinA=3/4
sin=p/h=3/4
p=3,h=4,b=?
h^2=p^2+b^2
h^2=3^2+4^2
h^2=9+16
h^2=25
h=5
we know that cosA=b/h
cosA=5/4
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