if sin A =3/4 find cos A and tan A
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Step-by-step explanation:
sin A = 3/4
(sinA )^2 + ( cos A ) ^2 = 1. ... ( identity )
(3/4)^2. + (cos A)^2 = 1
9/16. + ( cos A) ^ 2= 1
cos A ^2. = 1-9/16
cos A ^2. = 16-9/16
cos A ^2. =. 2√2 / 4 taking squareroot
tan A = sin A / cosA
= 3/4 × 4/ 2
tanA= 3/2√2
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