Question

If sin A = 3/4 , Find cos A and tan A.​

Answer 1

Answer:

sin A = P/H = 3/4

According to Pythagoras theorem,

H² = P²+B²

B² = H²-P²

B² = 16 - 9 = 7

B = √7

cos A = B/H = √7/4

tan A = P/B = 3/√7

Answer 2

Answer:

Hey mate here is your answer

Step-by-step explanation:

SinA=3/4=p/h

P=3x & h=4x

Thus by Pythagoras......b=√7

➡️CosA=√7/4=b/h

➡️TanA=3/√7=p/b

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