Question

If
Sin A: 3/4
find tan A

​

Answer 1

Step-by-step explanation:

this is solution

from trinogometry

Answer 2

Answer:

Step-by-step explanation:

GIven

SinA = 3/4

P/H = 3/4

=> P = 3K and H = 4K

So by using pythagoras theorem we can find out B

$H^{2} = P^{2} + B^{2} \\(4k)^{2} = (3k)^{2} + B^{2} \\16k^{2} = 9k^{2} + B^{2} \\16k^{2} - 9k^{2} = B^{2} \\B = \sqrt{7k^{2} } \\B = k\sqrt{7}$

We know tan A = P/B

                          = $3k/k\sqrt{7}$

                          = $3/\sqrt{7}$

Hope the solution is clear to you. :)