Question

If sin A=3/4,then caculate the value of cos A and tan A.​

Answer 1

Answer is... Given in attachment

Answer 2

Given:sinA=3/4

then let opposite side be 3k

and let hypotenuse be 4k

then by using Pythagoras Theorem a

${3}^{2} + {x}^{2} = {4}^{2}$

$x = \sqrt{16 - 9}$

$x = \sqrt{7}$

ie adjacent side

$= \sqrt{7k}$

cosA=

$\sqrt{7} \div 4$

tanA

$= 3 \div \sqrt{7}$