Question

If sin A = 3/4
then calculate cos A and tan A.​

Answer 1

sin²A+cos²A=1

cosA=√(1-sin²A)

cosA=√(1-(3/4))²=√(1-9/16)=√(7/16)=√7/3

tgA=sinA/cosA=(3/4)/(√7/3)=9/4√7=9√7/4