Question

if sin A = 3/4 Then Evaluate cos A and Tan A .....​

Answer 1

Step-by-step explanation:

if sinA =3/4

I.e., perpendicular =3 and the hypotenuse = 4

now 1st we have to find base by Pythagoras theorem

${p}^{2} + {b }^{2} equals \: to \: {h}^{2}$

here,

3^2 + b^2 = 4^2

then,

9+ b^2 =16

then,

b^2 = 7

so,

b = root 7

now,

cosA= root7/4

and

tanA=3/root4.

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Answer 2

If sinA = 3/4

cosA = 4/3

tanA = 3/4

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