Math, asked by devansh0404p3dit4, 1 year ago

If sin A = 3/5, 0<A< π/2 and cos B = -12/13, π<B<3π/2, find the following

(I) sin (A-B) (ii) cos (A+B) (iii) tan (A-B)

Answers

Answered by odedarahitesh6p7je14
2
1)sin(A-B)=sinAcosB-cosAsinB
2)cos(A-B)=cosAcosB-sinAsinB
3)Tan(A-B)=tanA-tanB/1+tanATanB
Insert value in the above equation
CosA=root1-9/25
=4/25

devansh0404p3dit4: How to obtain values of sin B and cos A
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