Question

if sin A= 3/5 and A is acute. find sin2A and cos2A​

Answer 1

Answer:

Step-by-step explanation:

Given sinA =3/5

Sin theta=opposite /hypotenuse

Also it forms a right angle triangle with sides 3 ,4 and hypotenuse 5

From this cosA =4/5

sin2A =2sinAcosA=2(3/5)(4/5)=24/25

cos2A=2cos²A-1=2(4/5)²-1=2(16/25)-1=32/25-1

=7/25

Answer 2

Answer:

Sin2A=24/25

Cos2A=7/25