If sin A= 3/5 and A lies in the first quadrant, the value of tan A+1/cosA
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If sinA=
5
3
and A is not in the first quadrant then find
tanA+secA
cosA+sin2A
.
Medium
Solution
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Correct option is C)
cosA=
1−sin
2
A
=
1−(
5
3
)
2
=
1−
25
9
=
25
16
=−
5
4
(A is in the second Quadrant)
Now,
tanA+secA
cosA+sin2A
=
cosA
sinA
+
cosA
1
cosA+2sinAcosA
=
1+sinA
cos
2
A(1+2sinA)
=
1+
5
3
(−
5
4
)
2
[1+2∗
5
3
]
=
25
16
∗
5
8
5
11
=
25
22
Therefore, Answer is
25
22
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