Question

If sin A = 3/5 evaluate cosA _1/tanA / 2cotA

Answer 1

Explanation:

sinA=3/5

$cos = \sqrt{1 - {sin}^{2} a }$

$\sqrt{1 - \frac{9}{25} }$

$\frac{4}{5}$

tanA=sinA/cosA

=3/5/4/5

=3/4

2cotA=2×cosA/sinA

=2×4/5/3/5

=2×4/3

=8/3

Answer 2

Answer:

sinA=3/5

cos = \sqrt{1 - {sin}^{2} a }cos=

1−sin

2

a

\sqrt{1 - \frac{9}{25} }

1−

25

9

\frac{4}{5}

5

4

tanA=sinA/cosA

=3/5/4/5

=3/4

2cotA=2×cosA/sinA

=2×4/5/3/5

=2×4/3

=8/3