if sin A =3/5 find @√1-cosA/1+cosA
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We know that
sin A = 3/5 = P/H
so Perpendicular = 3 and Hypotenuse = 5
Then by Pythagoras theorem Base = 4
Now according to question
√1-cosA/1+cosA
= √ [1-(4/5)]/[1+(4/5)]
=√ [1/5]/[9/5]
= √ 1/9
= ±1/3
HOPE THIS HELP YOU ☺☺
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