Question

If sin A × 3/5 find cos A and tan A

Answer 1

Answer:

if sinA =3/5

then cosA =√1-9/25

or, cosA=4/5

therefore tanA=sinA/cosA=3/4

Answer 2

Answer:

sinA= 3/5

sinA = opposite side /hypotenuse side

let consider triangle

b

|\

3| \ 5

|_ø\

c 4 a

according to Pythagoras rule

hypotenuse² = side² + side²

5² = 3²+side²

side²= 25-9

side = √16 = 4

cos A = adjacent side /hypotenuse side

cos A = 4/5

tan A = sinA/cosA

tan A = opposite side/Adjacent side

tan A = 3/4

very happy to get this answer in this beautiful way.

,thanku and ur question