Question

If sin A =3/5 find sin A cos B + cos A sin B where Angle C = 90°​

Answer 1

Step-by-step explanation:

sinA=3/5.=p/h

p=3

h=5

by Pythagoras theorem

b=√h2-p2

=√25-9

=√16

=4

cosA=4/5

sinB= 4/5

cosB=3/5

Now,

sinA cosB+ cosA sinB

=3/5*3/5+4/5*4/5

=9/25+16/25

=25/25

=1

Answer 2

Answer:

Step-by-step explanation:

sinA=3/5.=p/h

p=3

h=5

by Pythagoras theorem

b=√h2-p2

=√25-9

=√16

=4

cosA=4/5

sinB= 4/5

cosB=3/5

Now,

sinA cosB+ cosA sinB

=3/5*3/5+4/5*4/5

=9/25+16/25

=25/25

=1