If sin A =3/5;find sin2A
Cos 2A.
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Sin A = 3/5
Sin 2A = 3/5 x 2 = 6/5
CosA = 1/SinA
Therefore Cos2A = 10/6 = 5/3
Sin 2A = 3/5 x 2 = 6/5
CosA = 1/SinA
Therefore Cos2A = 10/6 = 5/3
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