Question

if sin A=3/5, find sinA+cosA/sinA-cosA​

Answer 1

Answer:

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Answer 2

$7.$

Step-by-step explanation:

$\sin(a) = \: \frac{opp}{hyp} = \frac{3}{5}.$

$let \: ac = 5 \: and \: ab = 3.$

${ac}^{2} = {ab}^{2} + {bc}^{2}.$

${5}^{2} = {3}^{2} + {bc}^{2} .$

$25 = 9 + {bc}^{2}.$

$25 - 9 = {bc}^{2}.$

$16 = {bc}^{2}.$

$\sqrt{16} = bc.$

$4 = bc.$

$\cos(a) = \frac{adj}{hyp} = \frac{4}{5} .$

$\frac{ \sin a + \cos \: a }{ \sin \: a - \cos \: a } .$

$\frac{ \frac{ \frac{3}{5} + \frac{4}{5} }{3} }{5} - \frac{4}{5}.$

$\frac{ \frac{ \frac{15 + 20}{5} }{15 - 20} }{5}.$

$\frac{ \frac{ \frac{35}{5} }{ - 5} }{5}.$

$\frac{35}{5} \times \frac{5}{5}.$

$7 \times 1$

$= 7.$