if sin A =3/5 find that tan A
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Answered by
1
it is very easy yrr
sin a= 3/5 p/h
using Pythagoras theorem
b square = h square - p square
b square = 5 square - 3 square
b square = 25-9
b square = 16
b=√16
b=4
tan a = p/b= 3/4 is answer
sin a= 3/5 p/h
using Pythagoras theorem
b square = h square - p square
b square = 5 square - 3 square
b square = 25-9
b square = 16
b=√16
b=4
tan a = p/b= 3/4 is answer
Answered by
0
Hi friend...
sin A = 3/5 (which is opposite side /hypotenuse)
Then 3 is opposite side and 5 is the hypotenuse.
Then let the adjacent side be x.
By Pythagoras theorem,
5^2 = x^2 + 3^2
25=x^2+9 (by transposing)
25-9= x^2
16 = x^2
(root of 16) 4=x.
tan A= opposite side /adjacent side
= 3/4.
Hope it helps
please mark it as brainliest if you find it useful friend :-)
sin A = 3/5 (which is opposite side /hypotenuse)
Then 3 is opposite side and 5 is the hypotenuse.
Then let the adjacent side be x.
By Pythagoras theorem,
5^2 = x^2 + 3^2
25=x^2+9 (by transposing)
25-9= x^2
16 = x^2
(root of 16) 4=x.
tan A= opposite side /adjacent side
= 3/4.
Hope it helps
please mark it as brainliest if you find it useful friend :-)
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