Question

if sin A = 3/5,tan B = 1/2 and π/2 <A<π<B<3π/2 then the value of 8 tan A^2-√5 sec B is​

Answer 1

8×(16/25) - √5×(-√5/2)

=7.42

Apply the formula 1. sin^2 x + cos^2 x = 1

2. tan^2 x+ 1 = sec^2 x