If sin A=3/5, then find cosA and tanA
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sinA 3/5
sin^2a=9/25
1-cos^2a=9/25
cos^2a =1-9/25
cos^2a=16/25
cosA=4/5
tanA=sinA /cosA a= 3/5 4/5 =3/4
hope it helps you..❤️❤️
Swapnil406:
Thanq
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