Question

if sin A =3/5 write the value of cos A​

Answer 1

sin A = 3/5 = P/H

h^2=p^2 +b^2

b^2 = 25- 9 =16

b = 4

cos A = b/h = 4/5

ans = 4/5

Answer 2

if sin A =3/5

therefore we know that ,

$sin { }^{2} a + cos {}^{2}a = 1$

cos^A=1-sin^A

=1-(3/5)^2

=1-9/25

=25-9/25

cos^A=16/25

cos A=√16/25

cos A=4/5

hope it helps you❤❤❤❤❤❤