Question

if sin A=√3 cos A, find the value of -1/
+1

Answer 1

Answer:

cosθ=cos60=21

sin  \theta = sin  60 =\frac{\sqrt{3}}{2}sin θ=sin 60=23

Step-by-step explanation:

Given : sin \theta = \sqrt{3} cos \thetasinθ=3cosθ

To Find : cos \thetacosθ and sin \thetasinθ

Solution :

\frac{sin \theta}{Cos \theta} = \sqrt{3}Cosθsinθ=3

tan \theta = \sqrt{3}tanθ=3

\theta = tan^{-1}\sqrt{3}θ=tan−13

\theta =60θ=60

cos \theta = cos 60 =\frac{1}{2}cosθ=cos60=21

sin  \theta = sin  60 =\frac{\sqrt{3}}{2}sin θ=sin 60=23