Question

If sin A = 3, then find the value of cosA + tan A.
5​

Answer 1

Answer:

Step-by-stetan A= 4/3

tan A=P/B

P= 4k, B=3k

By Pythagoras theorem

(H) ^2=(P) ^2+(B) ^2

(H) ^2=(4k) ^2+(3k) ^2

(H) ^2=16k^2+9k^2

(H) ^2=25k^2

H=5k

sinA=P/H=4k/5k=4/5

cosA=B/H=3k/5k=3/5

sinA+cosA/sinA-cosA

4/5+3/5/4/5-3/5

7/5/1/5

7/5×5/1

=7

Step-by-step explanation:

hope it will help uu ✌✌p explanation:

Answer 2

Sin=3 is not possible as value can’t exceed 1

So value of cosA +tanA is not feasible
If sin A = 3/5
Than problem becomes meaningfully as
CosA = 4/5
TanA = 3/4
So cosA + tanA = 4/5+3/4= 31/20