Question

If sin(A+36°)=cosA where A+36°is an acute angle then value of A.​

Answer 1

sin (A +36)= cos A

→cos (90-A-36)=cos A

→54-A = A

→A+A=54

→2A =54

→A =54/2

→A = 27

Answer 2

Solution :

In this Question We have to find the value of A When Sin(A+36°) = CosA Where A + 36° is an acute angle .

Sin (A + 36°) = CosA

⇒ Sin (A + 36°) = Sin ( 90 - A)

⇒ A + 36° = 90 - A

⇒ 2A  = 90 - 36

⇒ 2A = 54

⇒ A = 54/2

⇒ A = 27

Therefore , The required value of A is 27